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		<title>North of Sepo - new forum threads</title>
		<link>http://northofsepo.wikidot.com/forum/start</link>
		<description>Threads in forums of the site &quot;North of Sepo&quot; - ... where education rocks!</description>
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		<lastBuildDate>Wed, 16 May 2012 23:36:58 +0000</lastBuildDate>
		
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				<guid>http://northofsepo.wikidot.com/forum/t-468422</guid>
				<title>Surds - Year 10</title>
				<link>http://northofsepo.wikidot.com/forum/t-468422/surds-year-10</link>
				<description></description>
				<pubDate>Mon, 14 May 2012 12:31:25 +0000</pubDate>
				<wikidot:authorName>Wes Prosser</wikidot:authorName>				<wikidot:authorUserId>276877</wikidot:authorUserId>				<content:encoded>
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						 <p>Ask questions here about surds!</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-457114</guid>
				<title>Thank you!</title>
				<link>http://northofsepo.wikidot.com/forum/t-457114/thank-you</link>
				<description></description>
				<pubDate>Thu, 29 Mar 2012 03:52:58 +0000</pubDate>
				<wikidot:authorName>Da Man</wikidot:authorName>				<wikidot:authorUserId>1192098</wikidot:authorUserId>				<content:encoded>
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						 <p>Hey Wes!<br /> Just wanted to say a big thanks for your help! I did the test on saturday just gone and it went pretty well! So i am hopeful that this year will be the year :D Thanks for helping me grasp topics i have been struggling with! Next time i am down we will have to catch up so i can say thanks in person :D</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-447285</guid>
				<title>Chemical Thermodynamics</title>
				<link>http://northofsepo.wikidot.com/forum/t-447285/chemical-thermodynamics</link>
				<description>Questions from Worksheet 5 (Jan 2012)</description>
				<pubDate>Sat, 03 Mar 2012 04:02:26 +0000</pubDate>
				<wikidot:authorName>Wes Prosser</wikidot:authorName>				<wikidot:authorUserId>276877</wikidot:authorUserId>				<content:encoded>
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						 <p><span style="color: blue">Q 8.65</span> A system absorbs 300&#160;J heat and has 700&#160;J of work done on it. What is <span style="white-space: pre-wrap;">Δ</span>U? Is this overall endothermic or exothermic?</p> <hr /> <p><span style="white-space: pre-wrap;">Δ</span>U = +300&#160;J + +700J = +1000&#160;J <span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span><br /> System is endothermic as it has absorbed heat. <span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span></p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-446978</guid>
				<title>Chemical Reactions and Stoichiometry</title>
				<link>http://northofsepo.wikidot.com/forum/t-446978/chemical-reactions-and-stoichiometry</link>
				<description>Questions from Worksheets 3 &amp; 4 (Jan 2012)</description>
				<pubDate>Fri, 02 Mar 2012 10:53:36 +0000</pubDate>
				<wikidot:authorName>Wes Prosser</wikidot:authorName>				<wikidot:authorUserId>276877</wikidot:authorUserId>				<content:encoded>
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						 <p><span style="color: blue">Q 3.30</span> Balance the following equations:<br /> (a) Ca(OH)<sub>2</sub> + HCl <span style="white-space: pre-wrap;">→</span> CaCl<sub>2</sub> + H<sub>2</sub>O<br /> (b) AgNO<sub>3</sub> + CaCl<sub>2</sub> <span style="white-space: pre-wrap;">→</span> Ca(NO<sub>3</sub>)<sub>2</sub> + AgCl<br /> (c) Fe<sub>2</sub>O<sub>3</sub> + C <span style="white-space: pre-wrap;">→</span> Fe + CO<sub>2</sub><br /> (d) NaHCO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub> <span style="white-space: pre-wrap;">→</span> Na<sub>2</sub>SO<sub>4</sub> + H<sub>2</sub>O + CO<sub>2</sub><br /> (e) C<sub>4</sub>H<sub>10</sub> + O<sub>2</sub> <span style="white-space: pre-wrap;">→</span> CO<sub>2</sub> + H<sub>2</sub>O</p> <hr /> <p>(a) Ca(OH)<sub>2</sub> + 2HCl <span style="white-space: pre-wrap;">→</span> CaCl<sub>2</sub> + 2H<sub>2</sub>O <span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span><br /> (b) 2AgNO<sub>3</sub> + CaCl<sub>2</sub> <span style="white-space: pre-wrap;">→</span> Ca(NO<sub>3</sub>)<sub>2</sub> + 2AgCl <span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span><br /> (c) 2Fe<sub>2</sub>O<sub>3</sub> + 3C <span style="white-space: pre-wrap;">→</span> 4Fe + 3CO<sub>2</sub> <span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span><br /> (d) 2NaHCO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub> <span style="white-space: pre-wrap;">→</span> Na<sub>2</sub>SO<sub>4</sub> + 2H<sub>2</sub>O + 2CO<sub>2</sub> <span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span><br /> (e) C<sub>4</sub>H<sub>10</sub> + 6<span style="white-space: pre-wrap;">½</span>O<sub>2</sub> <span style="white-space: pre-wrap;">→</span> 4CO<sub>2</sub> + 5H<sub>2</sub>O<br /> <span style="white-space: pre-wrap;">∴</span> 2C<sub>4</sub>H<sub>10</sub> + 13O<sub>2</sub> <span style="white-space: pre-wrap;">→</span> 8CO<sub>2</sub> + 10H<sub>2</sub>O</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-446967</guid>
				<title>Language of Chemistry</title>
				<link>http://northofsepo.wikidot.com/forum/t-446967/language-of-chemistry</link>
				<description>Questions from Worksheet 2 (Jan 2012)</description>
				<pubDate>Fri, 02 Mar 2012 09:52:31 +0000</pubDate>
				<wikidot:authorName>Wes Prosser</wikidot:authorName>				<wikidot:authorUserId>276877</wikidot:authorUserId>				<content:encoded>
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						 <p><span style="color: blue">Q 2.44</span> Name the family to which each compound belongs.<br /> (a) CH<sub>3</sub>CH=CH<sub>2</sub><br /> (b) CH<sub>3</sub>CH<sub>2</sub>CH<sub>2</sub>COOH<br /> (c) CH<sub>3</sub>CH<sub>2</sub>OH<br /> (d) HOCH<sub>2</sub>CH<sub>2</sub>CH<sub>3</sub></p> <hr /> <p>(a) Has a C=C (carbon-carbon double bond), therefore is an Alkene. <span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span><br /> (b) Has a -COOH (carboxyl group), therefore is a Carboxylic Acid.<br /> (c) Has a -OH (hydroxyl group), therefore is an Alcohol. <span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span><br /> (d) Has a -OH (hydroxyl group), therefore is an Alcohol. <span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span></p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-446966</guid>
				<title>Mass Ratio</title>
				<link>http://northofsepo.wikidot.com/forum/t-446966/mass-ratio</link>
				<description>Questions from Worksheet 1 (Jan 2012)</description>
				<pubDate>Fri, 02 Mar 2012 09:39:11 +0000</pubDate>
				<wikidot:authorName>Wes Prosser</wikidot:authorName>				<wikidot:authorUserId>276877</wikidot:authorUserId>				<content:encoded>
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						 <p><span style="color: blue">Q 1.35</span> Laughing gas has 1.75g of Nitrogen for every 1g of Oxygen. Which is laughing gas?<br /> (a) 6.35g N, 7.26g O<br /> (b) 4.63g N, 10.58g O<br /> (c) 8.84g N, 5.05g O<br /> (d) 9.62g N, 16.5g O<br /> (e) 14.3g N, 40.0g O</p> <hr /> <p>(a) 6.35g N : 7.26g O = 0.875g N : 1.00g O<br /> (b) 4.63g N : 10.58g O = 0.438g N : 1.00g O<br /> (c) 8.84g N : 5.05g O = 1.75g N : 1.00g O<br /> (d) 9.62g N : 16.5g O = 0.583g N : 1.00g O<br /> (e) 14.3g N : 40.0g O = 0.358g N : 1.00g O<br /> Therefore (c) is the correct answer.</p> <p><span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span> As you mention, m(N) needs to be bigger than m(O), so you can <em>quickly</em> jump to the correct answer.</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-414607</guid>
				<title>Topics to talk about</title>
				<link>http://northofsepo.wikidot.com/forum/t-414607/topics-to-talk-about</link>
				<description></description>
				<pubDate>Wed, 23 Nov 2011 10:15:09 +0000</pubDate>
				<wikidot:authorName>Da Man</wikidot:authorName>				<wikidot:authorUserId>1192098</wikidot:authorUserId>				<content:encoded>
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						 <p>This is a thread for me to list topics that we might need to discuss due to difficulty in the concept etc:<br /> Atomic and hybrid orbitals</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-401598</guid>
				<title>Calculations using exponentials and logs</title>
				<link>http://northofsepo.wikidot.com/forum/t-401598/calculations-using-exponentials-and-logs</link>
				<description></description>
				<pubDate>Mon, 17 Oct 2011 10:02:08 +0000</pubDate>
				<wikidot:authorName>Da Man</wikidot:authorName>				<wikidot:authorUserId>1192098</wikidot:authorUserId>				<content:encoded>
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						 <p>Wes!<br /> I have started doing Acid/base questions and getting into pH. One issue i currently have is i have no idea how to do exponential and log calculations on a standard scientific calculator. Is you able to help?</p> <p>example of a expo q is 1.0 x 10^-14/4.4 x 10^-8 kind of thing. The majority of the pH questions i am guessing are -log's as well</p> <p>Hope your well and work has settled down a little!</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-390927</guid>
				<title>Empirical Formula</title>
				<link>http://northofsepo.wikidot.com/forum/t-390927/empirical-formula</link>
				<description></description>
				<pubDate>Thu, 15 Sep 2011 04:00:13 +0000</pubDate>
				<wikidot:authorName>Wes Prosser</wikidot:authorName>				<wikidot:authorUserId>276877</wikidot:authorUserId>				<content:encoded>
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						 <p>Q: A white powder has %mass of Ba 69.6%, C 6.09% and O 24.3%. What is the empirical formula? (M(Ba) = 137.3&#160;g mol<sup>-1</sup>, M(C) = 12.01&#160;g mol<sup>-1</sup>, M(O) = 16.00&#160;g mol<sup>-1</sup>)<br /> <span style="color: blue">(Worksheet 6)</span></p> <p>In a 100&#160;g sample, m(Ba) = 69.6&#160;g, m(C) = 6.09g, and m(O) = 24.3&#160;g<br /> n(Ba) = m(Ba) <span style="white-space: pre-wrap;">÷</span> M(Ba) = 69.6 <span style="white-space: pre-wrap;">÷</span> 137.3 = 0.507&#160;mol<br /> n(C) = m(C) <span style="white-space: pre-wrap;">÷</span> M(C) = 6.09 <span style="white-space: pre-wrap;">÷</span> 12.01 = 0.507&#160;mol<br /> n(O) = m(O) <span style="white-space: pre-wrap;">÷</span> M(O) = 24.3 <span style="white-space: pre-wrap;">÷</span> 16.00 = 1.52&#160;mol<br /> Mole ratio is 0.507 : 0.507 : 1.52 = <span class="math-inline">$\frac{0.507}{0.507} : \frac{0.507}{0.507} : \frac{1.52}{0.507}$</span> = 1 : 1 : 3<br /> Therefore, the empirical formula is BaCO<sub>3</sub></p> <p><span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span> Total blitz!</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-390918</guid>
				<title>Find Mass</title>
				<link>http://northofsepo.wikidot.com/forum/t-390918/find-mass</link>
				<description></description>
				<pubDate>Thu, 15 Sep 2011 03:08:02 +0000</pubDate>
				<wikidot:authorName>Wes Prosser</wikidot:authorName>				<wikidot:authorUserId>276877</wikidot:authorUserId>				<content:encoded>
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						 <p>Q: If a procedure can deposit 0.115&#160;mol of pure Ca<sub>3</sub>(PO<sub>4</sub>)<sub>2</sub> on an implant, what is the mass of the coating? Molar mass of Ca is 40.08&#160;g mol<sup>-1</sup>, of P is 30.97&#160;g mol<sup>-1</sup> and of O is 16.00&#160;g mol<sup>-1</sup>.<br /> <span style="color: blue">(Worksheet 1)</span></p> <p>M(Ca<sub>3</sub>(PO<sub>4</sub>)<sub>2</sub>) = 3 <span style="white-space: pre-wrap;">×</span> 40.08 + 2 <span style="white-space: pre-wrap;">×</span> 30.97 + 8 <span style="white-space: pre-wrap;">×</span> 16.00 = 310.2&#160;g mol<sup>-1</sup><br /> m = M <span style="white-space: pre-wrap;">×</span> n = 310.2 <span style="white-space: pre-wrap;">×</span> 0.115 = 35.7&#160;g</p> <p><span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span> All good!</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-390375</guid>
				<title>Find Moles</title>
				<link>http://northofsepo.wikidot.com/forum/t-390375/find-moles</link>
				<description></description>
				<pubDate>Tue, 13 Sep 2011 22:42:12 +0000</pubDate>
				<wikidot:authorName>Wes Prosser</wikidot:authorName>				<wikidot:authorUserId>276877</wikidot:authorUserId>				<content:encoded>
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						 <p>Q: A stone has a mass of 109.13g, and is made of pure carbon. Carbon has a molar mass of 12.01&#160;g mol<sup>-1</sup>. What is the amount of C?<br /> <span style="color: blue">(Worksheet 1)</span></p> <p>n = m <span style="white-space: pre-wrap;">÷</span> M = 109.13&#160;g <span style="white-space: pre-wrap;">÷</span> 12.01&#160;g mol<sup>-1</sup> = 9.087&#160;mol</p> <p><span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span> All good!</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-390359</guid>
				<title>Percentage Mass</title>
				<link>http://northofsepo.wikidot.com/forum/t-390359/percentage-mass</link>
				<description></description>
				<pubDate>Tue, 13 Sep 2011 22:30:14 +0000</pubDate>
				<wikidot:authorName>Wes Prosser</wikidot:authorName>				<wikidot:authorUserId>276877</wikidot:authorUserId>				<content:encoded>
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						 <p>Q: A sample of hydrocarbon of mass 8.657&#160;g has composition of 5.217&#160;g of C, 0.9620&#160;g H and 2.478&#160;g of O. What is the % composition?<br /> <span style="color: blue">(Worksheet 4)</span></p> <p>% by mass is:<br /> %m(C) = m <span style="white-space: pre-wrap;">÷</span> m = 5.217 <span style="white-space: pre-wrap;">÷</span> 8.657 <span style="white-space: pre-wrap;">×</span> 100 = 60.25%<br /> %m(H) = m <span style="white-space: pre-wrap;">÷</span> m = 0.962 <span style="white-space: pre-wrap;">÷</span> 8.657 <span style="white-space: pre-wrap;">×</span> 100 = 11.11%<br /> %m(O) = m <span style="white-space: pre-wrap;">÷</span> m = 2.478 <span style="white-space: pre-wrap;">÷</span> 8.657 <span style="white-space: pre-wrap;">×</span> 100 = 28.62%</p> <p><span style="color: lime"><span style="white-space: pre-wrap;">✓</span></span> Yep all good. Although, the question should specify % composition <em>by mass</em>, 'cos you could do % composition <em>by molarity</em>:</p> <p>% by moles is:<br /> n(C) = m <span style="white-space: pre-wrap;">÷</span> M = 5.217 <span style="white-space: pre-wrap;">÷</span> 12.01 = 0.4344&#160;mol<br /> n(H) = m <span style="white-space: pre-wrap;">÷</span> M = 0.962 <span style="white-space: pre-wrap;">÷</span> 1.008 = 0.9544&#160;mol<br /> n(O) = m <span style="white-space: pre-wrap;">÷</span> M = 2.478 <span style="white-space: pre-wrap;">÷</span> 16.00 = 0.1549&#160;mol<br /> %n(C) = 0.4344 <span style="white-space: pre-wrap;">÷</span> (0.4344 + 0.9544 + 0.1549) <span style="white-space: pre-wrap;">×</span> 100 = 28.14%<br /> %n(H) = 0.9544 <span style="white-space: pre-wrap;">÷</span> (0.4344 + 0.9544 + 0.1549) <span style="white-space: pre-wrap;">×</span> 100 = 61.83%<br /> %n(O) = 0.1549 <span style="white-space: pre-wrap;">÷</span> (0.4344 + 0.9544 + 0.1549) <span style="white-space: pre-wrap;">×</span> 100 = 10.03%</p> <p>By mass is common, but not very useful from a chemical perspective. By moles is less common, but more useful. Bit twisted, hey?</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-389939</guid>
				<title>Work Sheets</title>
				<link>http://northofsepo.wikidot.com/forum/t-389939/work-sheets</link>
				<description></description>
				<pubDate>Mon, 12 Sep 2011 10:35:11 +0000</pubDate>
				<wikidot:authorName>Da Man</wikidot:authorName>				<wikidot:authorUserId>1192098</wikidot:authorUserId>				<content:encoded>
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						 <p><a href="http://www.mediafire.com/?r55e4b8jbhno88n">http://www.mediafire.com/?r55e4b8jbhno88n</a></p> <p>Hey wes, these are the first set of work sheets. You able to check them out? :D</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-388789</guid>
				<title>Text Books</title>
				<link>http://northofsepo.wikidot.com/forum/t-388789/text-books</link>
				<description>Text book discussion for self directed learning for GAMSAT Science</description>
				<pubDate>Thu, 08 Sep 2011 09:15:54 +0000</pubDate>
				<wikidot:authorName>Da Man</wikidot:authorName>				<wikidot:authorUserId>1192098</wikidot:authorUserId>				<content:encoded>
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						 <p>Hello All<br /> Thought perhaps the best point to start would be discussion around text books/study material. Basically im utilising 3 books<br /> 1) The Gold standard GAMSAT -&gt; commercially available GAMSAT prep book that i got of ebay. Covers all the major science topics in decent detail and helps provide good direction for study<br /> 2) Chemistry by Blackman et al (2008) -&gt; a required text for 1st year chemistry students at UQ, has practice questions, worked examples etc and goes into subjects in a lot more detail. Used for cross referencing and to assisst in under standing topics that other books dont' explain well. Down side is has no answers for the questions (enter the Wes man)<br /> 3) Physics for Scientists and engineers 2nd edition by Knight. Used in the same way as Chemistry and same issues re answers.</p> <p>Just wanting to see if anyone would suggest any other text books that they think are good, explain things wells etc</p> <p>DaMan</p> 
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				<guid>http://northofsepo.wikidot.com/forum/t-307828</guid>
				<title>Notes To Self</title>
				<link>http://northofsepo.wikidot.com/forum/t-307828/notes-to-self</link>
				<description></description>
				<pubDate>Mon, 14 Feb 2011 06:22:06 +0000</pubDate>
				<wikidot:authorName>Wes Prosser</wikidot:authorName>				<wikidot:authorUserId>276877</wikidot:authorUserId>				<content:encoded>
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						 <p>Learning Goals:</p> <ul> <li>"Understand the basic concepts of computer programming"</li> <li>"Learn how to write programs for Turtle Graphics as a simple example of computer programming"</li> </ul> <p>Performance Goals:</p> <ul> <li>"Draw a square using Turtle Graphics"</li> </ul> 
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